(2x+25)=(3x-6)+(x+11)

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Solution for (2x+25)=(3x-6)+(x+11) equation: 



(2x+25)=(3x-6)+(x+11)

We move all terms to the left:

(2x+25)-((3x-6)+(x+11))=0

We get rid of parentheses

2x-((3x-6)+(x+11))+25=0



We calculate terms in parentheses: -((3x-6)+(x+11)), so:

(3x-6)+(x+11)

We get rid of parentheses

3x+x-6+11

We add all the numbers together, and all the variables

4x+5

Back to the equation:

-(4x+5)



We get rid of parentheses

2x-4x-5+25=0

We add all the numbers together, and all the variables

-2x+20=0

We move all terms containing x to the left, all other terms to the right

-2x=-20

x=-20/-2

x=+10

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