(2x+2)5x=135

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Solution for (2x+2)5x=135 equation:



(2x+2)5x=135
We move all terms to the left:
(2x+2)5x-(135)=0
We multiply parentheses
10x^2+10x-135=0
a = 10; b = 10; c = -135;
Δ = b2-4ac
Δ = 102-4·10·(-135)
Δ = 5500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{5500}=\sqrt{100*55}=\sqrt{100}*\sqrt{55}=10\sqrt{55}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10\sqrt{55}}{2*10}=\frac{-10-10\sqrt{55}}{20} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10\sqrt{55}}{2*10}=\frac{-10+10\sqrt{55}}{20} $

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