6(c+4)=4(c-18)

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Solution for 6(c+4)=4(c-18) equation: 



6(c+4)=4(c-18)

We move all terms to the left:

6(c+4)-(4(c-18))=0

We multiply parentheses

6c-(4(c-18))+24=0



We calculate terms in parentheses: -(4(c-18)), so:

4(c-18)

We multiply parentheses

4c-72

Back to the equation:

-(4c-72)



We get rid of parentheses

6c-4c+72+24=0

We add all the numbers together, and all the variables

2c+96=0

We move all terms containing c to the left, all other terms to the right

2c=-96

c=-96/2

c=-48

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