(2x+2)/11=(x-4)/6

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Solution for (2x+2)/11=(x-4)/6 equation: 



(2x+2)/11=(x-4)/6

We move all terms to the left:

(2x+2)/11-((x-4)/6)=0

We calculate fractions


2x/()+(-((x-4)*11)/()=0



We calculate terms in parentheses: +(-((x-4)*11)/(), so:

-((x-4)*11)/(

We multiply all the terms by the denominator


-((x-4)*11)



We calculate terms in parentheses: -((x-4)*11), so:

(x-4)*11

We multiply parentheses

11x-44

Back to the equation:

-(11x-44)



We get rid of parentheses

-11x+44

Back to the equation:

+(-11x+44)



We get rid of parentheses

2x/()-11x+44=0

We multiply all the terms by the denominator


2x-11x*()+44*()=0

We add all the numbers together, and all the variables

2x-11x*()=0

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