(2x+2)+(3x+6)=48

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Solution for (2x+2)+(3x+6)=48 equation:



(2x+2)+(3x+6)=48
We move all terms to the left:
(2x+2)+(3x+6)-(48)=0
We get rid of parentheses
2x+3x+2+6-48=0
We add all the numbers together, and all the variables
5x-40=0
We move all terms containing x to the left, all other terms to the right
5x=40
x=40/5
x=8

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