4n+(6-2n)=2(n+3)

Solution for 4n+(6-2n)=2(n+3) equation:

4n+(6-2n)=2(n+3)

We move all terms to the left:

4n+(6-2n)-(2(n+3))=0

We add all the numbers together, and all the variables

4n+(-2n+6)-(2(n+3))=0

We get rid of parentheses

4n-2n-(2(n+3))+6=0


We calculate terms in parentheses: -(2(n+3)), so:

2(n+3)

We multiply parentheses

2n+6

Back to the equation:

-(2n+6)


We add all the numbers together, and all the variables

2n-(2n+6)+6=0

We get rid of parentheses

2n-2n-6+6=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0