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(2x+2)(3x-6)=0
We multiply parentheses ..
(+6x^2-12x+6x-12)=0
We get rid of parentheses
6x^2-12x+6x-12=0
We add all the numbers together, and all the variables
6x^2-6x-12=0
a = 6; b = -6; c = -12;
Δ = b2-4ac
Δ = -62-4·6·(-12)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-18}{2*6}=\frac{-12}{12} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+18}{2*6}=\frac{24}{12} =2 $
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