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(1/4)(x+12)-5=(2/3)x+7
We move all terms to the left:
(1/4)(x+12)-5-((2/3)x+7)=0
Domain of the equation: 4)(x+12)!=0
x∈R
Domain of the equation: 3)x+7)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/4)(x+12)-((+2/3)x+7)-5=0
We multiply parentheses ..
(+x^2+1/4*12)-((+2/3)x+7)-5=0
We calculate fractions
We do not support expression: x^3
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