(2x+16)+(2x+10)+(180-(6x-12))=180

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Solution for (2x+16)+(2x+10)+(180-(6x-12))=180 equation: 



(2x+16)+(2x+10)+(180-(6x-12))=180

We move all terms to the left:

(2x+16)+(2x+10)+(180-(6x-12))-(180)=0

We get rid of parentheses

2x+2x+(180-(6x-12))+16+10-180=0



We calculate terms in parentheses: +(180-(6x-12)), so:

180-(6x-12)

determiningTheFunctionDomain
-(6x-12)+180

We get rid of parentheses

-6x+12+180

We add all the numbers together, and all the variables

-6x+192

Back to the equation:

+(-6x+192)



We add all the numbers together, and all the variables

4x+(-6x+192)-154=0

We get rid of parentheses

4x-6x+192-154=0

We add all the numbers together, and all the variables

-2x+38=0

We move all terms containing x to the left, all other terms to the right

-2x=-38

x=-38/-2

x=+19

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