4(1-x)=4x-3(8x+4)

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Solution for 4(1-x)=4x-3(8x+4) equation: 



4(1-x)=4x-3(8x+4)

We move all terms to the left:

4(1-x)-(4x-3(8x+4))=0

We add all the numbers together, and all the variables

4(-1x+1)-(4x-3(8x+4))=0

We multiply parentheses

-4x-(4x-3(8x+4))+4=0



We calculate terms in parentheses: -(4x-3(8x+4)), so:

4x-3(8x+4)

We multiply parentheses

4x-24x-12

We add all the numbers together, and all the variables

-20x-12

Back to the equation:

-(-20x-12)



We get rid of parentheses

-4x+20x+12+4=0

We add all the numbers together, and all the variables

16x+16=0

We move all terms containing x to the left, all other terms to the right

16x=-16

x=-16/16

x=-1

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