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(2x+13)(x)=576
We move all terms to the left:
(2x+13)(x)-(576)=0
We multiply parentheses
2x^2+13x-576=0
a = 2; b = 13; c = -576;
Δ = b2-4ac
Δ = 132-4·2·(-576)
Δ = 4777
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{4777}}{2*2}=\frac{-13-\sqrt{4777}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{4777}}{2*2}=\frac{-13+\sqrt{4777}}{4} $
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