5(3-x)=(4+x)2

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Solution for 5(3-x)=(4+x)2 equation: 



5(3-x)=(4+x)2

We move all terms to the left:

5(3-x)-((4+x)2)=0

We add all the numbers together, and all the variables

5(-1x+3)-((x+4)2)=0

We multiply parentheses

-5x-((x+4)2)+15=0



We calculate terms in parentheses: -((x+4)2), so:

(x+4)2

We multiply parentheses

2x+8

Back to the equation:

-(2x+8)



We get rid of parentheses

-5x-2x-8+15=0

We add all the numbers together, and all the variables

-7x+7=0

We move all terms containing x to the left, all other terms to the right

-7x=-7

x=-7/-7

x=1

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