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(2x+12)(2x+18)=432
We move all terms to the left:
(2x+12)(2x+18)-(432)=0
We multiply parentheses ..
(+4x^2+36x+24x+216)-432=0
We get rid of parentheses
4x^2+36x+24x+216-432=0
We add all the numbers together, and all the variables
4x^2+60x-216=0
a = 4; b = 60; c = -216;
Δ = b2-4ac
Δ = 602-4·4·(-216)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-84}{2*4}=\frac{-144}{8} =-18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+84}{2*4}=\frac{24}{8} =3 $
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