3a-2(2a-5)=2(a+3)=8

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Solution for 3a-2(2a-5)=2(a+3)=8 equation: 



3a-2(2a-5)=2(a+3)=8

We move all terms to the left:

3a-2(2a-5)-(2(a+3))=0

We multiply parentheses

3a-4a-(2(a+3))+10=0



We calculate terms in parentheses: -(2(a+3)), so:

2(a+3)

We multiply parentheses

2a+6

Back to the equation:

-(2a+6)



We add all the numbers together, and all the variables

-1a-(2a+6)+10=0

We get rid of parentheses

-1a-2a-6+10=0

We add all the numbers together, and all the variables

-3a+4=0

We move all terms containing a to the left, all other terms to the right

-3a=-4

a=-4/-3

a=1+1/3

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