(2x+10)+(3x-9)+(6x-19)=180

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Solution for (2x+10)+(3x-9)+(6x-19)=180 equation: 



(2x+10)+(3x-9)+(6x-19)=180

We move all terms to the left:

(2x+10)+(3x-9)+(6x-19)-(180)=0

We get rid of parentheses

2x+3x+6x+10-9-19-180=0

We add all the numbers together, and all the variables

11x-198=0

We move all terms containing x to the left, all other terms to the right

11x=198

x=198/11

x=18

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