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5(x-3)-2/5(5x-10)=-1/2(6-8x)
We move all terms to the left:
5(x-3)-2/5(5x-10)-(-1/2(6-8x))=0
Domain of the equation: 5(5x-10)!=0
x∈R
Domain of the equation: 2(6-8x))!=0We add all the numbers together, and all the variables
x∈R
5(x-3)-2/5(5x-10)-(-1/2(-8x+6))=0
We multiply parentheses
5x-2/5(5x-10)-(-1/2(-8x+6))-15=0
We calculate fractions
5x+(-4x(-)/(5(5x-10)*2(-8x+6)))+(-(-5x5)/(5(5x-10)*2(-8x+6)))-15=0
We calculate terms in parentheses: +(-4x(-)/(5(5x-10)*2(-8x+6))), so:
-4x(-)/(5(5x-10)*2(-8x+6))
We add all the numbers together, and all the variables
-4x0/(5(5x-10)*2(-8x+6))
We multiply all the terms by the denominator
-4x0
We add all the numbers together, and all the variables
-4x
Back to the equation:
+(-4x)
We calculate terms in parentheses: +(-(-5x5)/(5(5x-10)*2(-8x+6))), so:
-(-5x5)/(5(5x-10)*2(-8x+6))
We add all the numbers together, and all the variables
-(-5x^5)/(5(5x-10)*2(-8x+6))
We multiply all the terms by the denominator
-(-5x^5)
We do not support expression: x^5
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