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(2x+1)/3+1=x
We move all terms to the left:
(2x+1)/3+1-(x)=0
We add all the numbers together, and all the variables
-1x+(2x+1)/3+1=0
We multiply all the terms by the denominator
-1x*3+(2x+1)+1*3=0
We add all the numbers together, and all the variables
-1x*3+(2x+1)+3=0
Wy multiply elements
-3x+(2x+1)+3=0
We get rid of parentheses
-3x+2x+1+3=0
We add all the numbers together, and all the variables
-1x+4=0
We move all terms containing x to the left, all other terms to the right
-x=-4
x=-4/-1
x=+4
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