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(2x+1)(x-1)=210
We move all terms to the left:
(2x+1)(x-1)-(210)=0
We multiply parentheses ..
(+2x^2-2x+x-1)-210=0
We get rid of parentheses
2x^2-2x+x-1-210=0
We add all the numbers together, and all the variables
2x^2-1x-211=0
a = 2; b = -1; c = -211;
Δ = b2-4ac
Δ = -12-4·2·(-211)
Δ = 1689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{1689}}{2*2}=\frac{1-\sqrt{1689}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{1689}}{2*2}=\frac{1+\sqrt{1689}}{4} $
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