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(5x+5)(2x+5)=305
We move all terms to the left:
(5x+5)(2x+5)-(305)=0
We multiply parentheses ..
(+10x^2+25x+10x+25)-305=0
We get rid of parentheses
10x^2+25x+10x+25-305=0
We add all the numbers together, and all the variables
10x^2+35x-280=0
a = 10; b = 35; c = -280;
Δ = b2-4ac
Δ = 352-4·10·(-280)
Δ = 12425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12425}=\sqrt{25*497}=\sqrt{25}*\sqrt{497}=5\sqrt{497}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-5\sqrt{497}}{2*10}=\frac{-35-5\sqrt{497}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+5\sqrt{497}}{2*10}=\frac{-35+5\sqrt{497}}{20} $
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