(2x+1)(4x+1)(6x+1)(12x+1)=2

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Solution for (2x+1)(4x+1)(6x+1)(12x+1)=2 equation: 



(2x+1)(4x+1)(6x+1)(12x+1)=2

We move all terms to the left:

(2x+1)(4x+1)(6x+1)(12x+1)-(2)=0

We multiply parentheses ..

(+8x^2+2x+4x+1)(6x+1)(12x+1)-2=0

We multiply parentheses ..

(+8x^2+2x+4x+1)(+72x^2+6x+12x+1)-2=0

We move all terms containing x to the left, all other terms to the right

(+8x^2+2x+4x+1)(+72x^2+6x+12x+1)=2

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