x+(1/4x)=150

Solution for x+(1/4x)=150 equation:

x+(1/4x)=150

We move all terms to the left:

x+(1/4x)-(150)=0


Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x+(+1/4x)-150=0

We get rid of parentheses

x+1/4x-150=0

We multiply all the terms by the denominator


x*4x-150*4x+1=0

Wy multiply elements

4x^2-600x+1=0

a = 4; b = -600; c = +1;
Δ = b2-4ac
Δ = -6002-4·4·1
Δ = 359984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{359984}=\sqrt{16*22499}=\sqrt{16}*\sqrt{22499}=4\sqrt{22499}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-600)-4\sqrt{22499}}{2*4}=\frac{600-4\sqrt{22499}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-600)+4\sqrt{22499}}{2*4}=\frac{600+4\sqrt{22499}}{8}
$