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(2x)/3+(3x)=99
We move all terms to the left:
(2x)/3+(3x)-(99)=0
We add all the numbers together, and all the variables
3x+2x/3-99=0
We multiply all the terms by the denominator
3x*3+2x-99*3=0
We add all the numbers together, and all the variables
2x+3x*3-297=0
Wy multiply elements
2x+9x-297=0
We add all the numbers together, and all the variables
11x-297=0
We move all terms containing x to the left, all other terms to the right
11x=297
x=297/11
x=27
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