8(h-2)+3h=2(3-h)+4

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Solution for 8(h-2)+3h=2(3-h)+4 equation: 



8(h-2)+3h=2(3-h)+4

We move all terms to the left:

8(h-2)+3h-(2(3-h)+4)=0

We add all the numbers together, and all the variables

8(h-2)+3h-(2(-1h+3)+4)=0

We add all the numbers together, and all the variables

3h+8(h-2)-(2(-1h+3)+4)=0

We multiply parentheses

3h+8h-(2(-1h+3)+4)-16=0



We calculate terms in parentheses: -(2(-1h+3)+4), so:

2(-1h+3)+4

We multiply parentheses

-2h+6+4

We add all the numbers together, and all the variables

-2h+10

Back to the equation:

-(-2h+10)



We add all the numbers together, and all the variables

11h-(-2h+10)-16=0

We get rid of parentheses

11h+2h-10-16=0

We add all the numbers together, and all the variables

13h-26=0

We move all terms containing h to the left, all other terms to the right

13h=26

h=26/13

h=2

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