(2x)(2x)=(x-10)(2x-3)

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Solution for (2x)(2x)=(x-10)(2x-3) equation: 



(2x)(2x)=(x-10)(2x-3)

We move all terms to the left:

(2x)(2x)-((x-10)(2x-3))=0

We multiply parentheses ..

-((+2x^2-3x-20x+30))+2x2x=0



We calculate terms in parentheses: -((+2x^2-3x-20x+30)), so:

(+2x^2-3x-20x+30)

We get rid of parentheses

2x^2-3x-20x+30

We add all the numbers together, and all the variables

2x^2-23x+30

Back to the equation:

-(2x^2-23x+30)



We get rid of parentheses

-2x^2+23x+2x2x-30=0

We move all terms containing x to the left, all other terms to the right

-2x^2+23x+2x2x=30

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