(2w-16)(16w-2)=0

Solution for (2w-16)(16w-2)=0 equation:

(2w-16)(16w-2)=0

We multiply parentheses ..

(+32w^2-4w-256w+32)=0

We get rid of parentheses

32w^2-4w-256w+32=0

We add all the numbers together, and all the variables

32w^2-260w+32=0

a = 32; b = -260; c = +32;
Δ = b2-4ac
Δ = -2602-4·32·32
Δ = 63504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{63504}=252$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-260)-252}{2*32}=\frac{8}{64}
=1/8
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-260)+252}{2*32}=\frac{512}{64}
=8
$