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(3w-21)(21w-3)=0
We multiply parentheses ..
(+63w^2-9w-441w+63)=0
We get rid of parentheses
63w^2-9w-441w+63=0
We add all the numbers together, and all the variables
63w^2-450w+63=0
a = 63; b = -450; c = +63;
Δ = b2-4ac
Δ = -4502-4·63·63
Δ = 186624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{186624}=432$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-450)-432}{2*63}=\frac{18}{126} =1/7 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-450)+432}{2*63}=\frac{882}{126} =7 $
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