(2v+7)(6-v)=0

Solution for (2v+7)(6-v)=0 equation:

(2v+7)(6-v)=0

We add all the numbers together, and all the variables

(2v+7)(-1v+6)=0

We multiply parentheses ..

(-2v^2+12v-7v+42)=0

We get rid of parentheses

-2v^2+12v-7v+42=0

We add all the numbers together, and all the variables

-2v^2+5v+42=0

a = -2; b = 5; c = +42;
Δ = b2-4ac
Δ = 52-4·(-2)·42
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-19}{2*-2}=\frac{-24}{-4}
=+6
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+19}{2*-2}=\frac{14}{-4}
=-3+1/2
$