(2k-2)=(k+2)=90

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Solution for (2k-2)=(k+2)=90 equation: 



(2k-2)=(k+2)=90

We move all terms to the left:

(2k-2)-((k+2))=0

We get rid of parentheses

2k-((k+2))-2=0



We calculate terms in parentheses: -((k+2)), so:

(k+2)

We get rid of parentheses

k+2

Back to the equation:

-(k+2)



We get rid of parentheses

2k-k-2-2=0

We add all the numbers together, and all the variables

k-4=0

We move all terms containing k to the left, all other terms to the right

k=4

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