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(2t-7)(6t+3)=(3t+6)(4t-5)
We move all terms to the left:
(2t-7)(6t+3)-((3t+6)(4t-5))=0
We multiply parentheses ..
(+12t^2+6t-42t-21)-((3t+6)(4t-5))=0
We calculate terms in parentheses: -((3t+6)(4t-5)), so:We get rid of parentheses
(3t+6)(4t-5)
We multiply parentheses ..
(+12t^2-15t+24t-30)
We get rid of parentheses
12t^2-15t+24t-30
We add all the numbers together, and all the variables
12t^2+9t-30
Back to the equation:
-(12t^2+9t-30)
12t^2-12t^2+6t-42t-9t-21+30=0
We add all the numbers together, and all the variables
-45t+9=0
We move all terms containing t to the left, all other terms to the right
-45t=-9
t=-9/-45
t=1/5
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