(2t+2)(8t)=t

Solution for (2t+2)(8t)=t equation:

(2t+2)(8t)=t

We move all terms to the left:

(2t+2)(8t)-(t)=0

We add all the numbers together, and all the variables

-1t+(2t+2)8t=0

We multiply parentheses

16t^2-1t+16t=0

We add all the numbers together, and all the variables

16t^2+15t=0

a = 16; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·16·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*16}=\frac{-30}{32}
=-15/16
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*16}=\frac{0}{32}
=0
$