7(x+10)+x=2(x+3)-4

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Solution for 7(x+10)+x=2(x+3)-4 equation: 



7(x+10)+x=2(x+3)-4

We move all terms to the left:

7(x+10)+x-(2(x+3)-4)=0

We add all the numbers together, and all the variables

x+7(x+10)-(2(x+3)-4)=0

We multiply parentheses

x+7x-(2(x+3)-4)+70=0



We calculate terms in parentheses: -(2(x+3)-4), so:

2(x+3)-4

We multiply parentheses

2x+6-4

We add all the numbers together, and all the variables

2x+2

Back to the equation:

-(2x+2)



We add all the numbers together, and all the variables

8x-(2x+2)+70=0

We get rid of parentheses

8x-2x-2+70=0

We add all the numbers together, and all the variables

6x+68=0

We move all terms containing x to the left, all other terms to the right

6x=-68

x=-68/6

x=-11+1/3

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