(2r+3)2+(r+4)2=10

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Solution for (2r+3)2+(r+4)2=10 equation: 



(2r+3)2+(r+4)2=10

We move all terms to the left:

(2r+3)2+(r+4)2-(10)=0

We multiply parentheses

4r+2r+6+8-10=0

We add all the numbers together, and all the variables

6r+4=0

We move all terms containing r to the left, all other terms to the right

6r=-4

r=-4/6

r=-2/3

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