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5(6x+10)(x-2)=0
We multiply parentheses ..
5(+6x^2-12x+10x-20)=0
We multiply parentheses
30x^2-60x+50x-100=0
We add all the numbers together, and all the variables
30x^2-10x-100=0
a = 30; b = -10; c = -100;
Δ = b2-4ac
Δ = -102-4·30·(-100)
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12100}=110$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-110}{2*30}=\frac{-100}{60} =-1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+110}{2*30}=\frac{120}{60} =2 $
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