(2q+4)7=6

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Solution for (2q+4)7=6 equation: 



(2q+4)7=6

We move all terms to the left:

(2q+4)7-(6)=0

We multiply parentheses

14q+28-6=0

We add all the numbers together, and all the variables

14q+22=0

We move all terms containing q to the left, all other terms to the right

14q=-22

q=-22/14

q=-1+4/7

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