(2p=12)+(3p-8)=

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Solution for (2p=12)+(3p-8)= equation: 



(2p=12)+(3p-8)=

We move all terms to the left:

(2p-(12)+(3p-8))=0



We calculate terms in parentheses: +(2p-12+(3p-8)), so:

2p-12+(3p-8)

determiningTheFunctionDomain
2p+(3p-8)-12

We get rid of parentheses

2p+3p-8-12

We add all the numbers together, and all the variables

5p-20

Back to the equation:

+(5p-20)



We get rid of parentheses

5p-20=0

We move all terms containing p to the left, all other terms to the right

5p=20

p=20/5

p=4

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