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2(x+3)=2+4(x-2)
We move all terms to the left:
2(x+3)-(2+4(x-2))=0
We multiply parentheses
2x-(2+4(x-2))+6=0
We calculate terms in parentheses: -(2+4(x-2)), so:We get rid of parentheses
2+4(x-2)
determiningTheFunctionDomain 4(x-2)+2
We multiply parentheses
4x-8+2
We add all the numbers together, and all the variables
4x-6
Back to the equation:
-(4x-6)
2x-4x+6+6=0
We add all the numbers together, and all the variables
-2x+12=0
We move all terms containing x to the left, all other terms to the right
-2x=-12
x=-12/-2
x=+6
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