(2p+1)/9=(p+6)/10

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Solution for (2p+1)/9=(p+6)/10 equation: 



(2p+1)/9=(p+6)/10

We move all terms to the left:

(2p+1)/9-((p+6)/10)=0

We calculate fractions


2p/()+(-((p+6)*9)/()=0



We calculate terms in parentheses: +(-((p+6)*9)/(), so:

-((p+6)*9)/(

We multiply all the terms by the denominator


-((p+6)*9)



We calculate terms in parentheses: -((p+6)*9), so:

(p+6)*9

We multiply parentheses

9p+54

Back to the equation:

-(9p+54)



We get rid of parentheses

-9p-54

Back to the equation:

+(-9p-54)



We get rid of parentheses

2p/()-9p-54=0

We multiply all the terms by the denominator


2p-9p*()-54*()=0

We add all the numbers together, and all the variables

2p-9p*()=0

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