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-2x+5x(3x-5)=-6-6x
We move all terms to the left:
-2x+5x(3x-5)-(-6-6x)=0
We add all the numbers together, and all the variables
-2x+5x(3x-5)-(-6x-6)=0
We multiply parentheses
15x^2-2x-25x-(-6x-6)=0
We get rid of parentheses
15x^2-2x-25x+6x+6=0
We add all the numbers together, and all the variables
15x^2-21x+6=0
a = 15; b = -21; c = +6;
Δ = b2-4ac
Δ = -212-4·15·6
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-9}{2*15}=\frac{12}{30} =2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+9}{2*15}=\frac{30}{30} =1 $
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