(2n+3)+(4n+5)=32

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Solution for (2n+3)+(4n+5)=32 equation: 



(2n+3)+(4n+5)=32

We move all terms to the left:

(2n+3)+(4n+5)-(32)=0

We get rid of parentheses

2n+4n+3+5-32=0

We add all the numbers together, and all the variables

6n-24=0

We move all terms containing n to the left, all other terms to the right

6n=24

n=24/6

n=4

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