(2m-3)(m-1)=3

Solution for (2m-3)(m-1)=3 equation:

(2m-3)(m-1)=3

We move all terms to the left:

(2m-3)(m-1)-(3)=0

We multiply parentheses ..

(+2m^2-2m-3m+3)-3=0

We get rid of parentheses

2m^2-2m-3m+3-3=0

We add all the numbers together, and all the variables

2m^2-5m=0

a = 2; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·2·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*2}=\frac{0}{4}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*2}=\frac{10}{4}
=2+1/2
$