/2x+16+3x=36

Solution for /2x+16+3x=36 equation:

/2x+16+3x=36

We move all terms to the left:

/2x+16+3x-(36)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

3x+/2x-20=0

We multiply all the terms by the denominator


3x*2x-20*2x+=0

We add all the numbers together, and all the variables

3x*2x-20*2x=0

Wy multiply elements

6x^2-40x=0

a = 6; b = -40; c = 0;
Δ = b2-4ac
Δ = -402-4·6·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-40}{2*6}=\frac{0}{12}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+40}{2*6}=\frac{80}{12}
=6+2/3
$