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(2m-1)(m-14)=0
We multiply parentheses ..
(+2m^2-28m-1m+14)=0
We get rid of parentheses
2m^2-28m-1m+14=0
We add all the numbers together, and all the variables
2m^2-29m+14=0
a = 2; b = -29; c = +14;
Δ = b2-4ac
Δ = -292-4·2·14
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-27}{2*2}=\frac{2}{4} =1/2 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+27}{2*2}=\frac{56}{4} =14 $
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