(2m+1)/9=(12-7m)/6

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Solution for (2m+1)/9=(12-7m)/6 equation: 



(2m+1)/9=(12-7m)/6

We move all terms to the left:

(2m+1)/9-((12-7m)/6)=0

We add all the numbers together, and all the variables

(2m+1)/9-((-7m+12)/6)=0

We calculate fractions


2m/()+(-((-7m+12)*9)/()=0



We calculate terms in parentheses: +(-((-7m+12)*9)/(), so:

-((-7m+12)*9)/(

We multiply all the terms by the denominator


-((-7m+12)*9)



We calculate terms in parentheses: -((-7m+12)*9), so:

(-7m+12)*9

We multiply parentheses

-63m+108

Back to the equation:

-(-63m+108)



We get rid of parentheses

63m-108

Back to the equation:

+(63m-108)



We get rid of parentheses

2m/()+63m-108=0

We multiply all the terms by the denominator


2m+63m*()-108*()=0

We add all the numbers together, and all the variables

2m+63m*()=0

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