3y=10/2y

Solution for 3y=10/2y equation:

3y=10/2y

We move all terms to the left:

3y-(10/2y)=0


Domain of the equation: 2y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

3y-(+10/2y)=0

We get rid of parentheses

3y-10/2y=0

We multiply all the terms by the denominator


3y*2y-10=0

Wy multiply elements

6y^2-10=0

a = 6; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·6·(-10)
Δ = 240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{240}=\sqrt{16*15}=\sqrt{16}*\sqrt{15}=4\sqrt{15}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{15}}{2*6}=\frac{0-4\sqrt{15}}{12}
=-\frac{4\sqrt{15}}{12}
=-\frac{\sqrt{15}}{3}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{15}}{2*6}=\frac{0+4\sqrt{15}}{12}
=\frac{4\sqrt{15}}{12}
=\frac{\sqrt{15}}{3}
$