(2k+1)2+(2k+3)2=(2k+5)2

Solution for (2k+1)2+(2k+3)2=(2k+5)2 equation:

(2k+1)2+(2k+3)2=(2k+5)2

We move all terms to the left:

(2k+1)2+(2k+3)2-((2k+5)2)=0

We multiply parentheses

4k+4k-((2k+5)2)+2+6=0


We calculate terms in parentheses: -((2k+5)2), so:

(2k+5)2

We multiply parentheses

4k+10

Back to the equation:

-(4k+10)


We add all the numbers together, and all the variables

8k-(4k+10)+8=0

We get rid of parentheses

8k-4k-10+8=0

We add all the numbers together, and all the variables

4k-2=0

We move all terms containing k to the left, all other terms to the right

4k=2

k=2/4

k=1/2