6(X+3)+4x-10=48

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Solution for 6(X+3)+4x-10=48 equation: 



6(X+3)+4X-10=48

We move all terms to the left:

6(X+3)+4X-10-(48)=0

We add all the numbers together, and all the variables

4X+6(X+3)-58=0

We multiply parentheses

4X+6X+18-58=0

We add all the numbers together, and all the variables

10X-40=0

We move all terms containing X to the left, all other terms to the right

10X=40

X=40/10

X=4

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