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(2h-4)1122h-44=2
We move all terms to the left:
(2h-4)1122h-44-(2)=0
We add all the numbers together, and all the variables
(2h-4)1122h-46=0
We multiply parentheses
2244h^2-4488h-46=0
a = 2244; b = -4488; c = -46;
Δ = b2-4ac
Δ = -44882-4·2244·(-46)
Δ = 20555040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{20555040}=\sqrt{16*1284690}=\sqrt{16}*\sqrt{1284690}=4\sqrt{1284690}$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4488)-4\sqrt{1284690}}{2*2244}=\frac{4488-4\sqrt{1284690}}{4488} $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4488)+4\sqrt{1284690}}{2*2244}=\frac{4488+4\sqrt{1284690}}{4488} $
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