7(z-4)=7z-28

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Solution for 7(z-4)=7z-28 equation: 



7(z-4)=7z-28

We move all terms to the left:

7(z-4)-(7z-28)=0

We multiply parentheses

7z-(7z-28)-28=0

We get rid of parentheses

7z-7z+28-28=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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