(2c+10)=(3c+2)

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Solution for (2c+10)=(3c+2) equation: 



(2c+10)=(3c+2)

We move all terms to the left:

(2c+10)-((3c+2))=0

We get rid of parentheses

2c-((3c+2))+10=0



We calculate terms in parentheses: -((3c+2)), so:

(3c+2)

We get rid of parentheses

3c+2

Back to the equation:

-(3c+2)



We get rid of parentheses

2c-3c-2+10=0

We add all the numbers together, and all the variables

-1c+8=0

We move all terms containing c to the left, all other terms to the right

-c=-8

c=-8/-1

c=+8

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