3/2(d+12)=1/2(d-6)

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Solution for 3/2(d+12)=1/2(d-6) equation: 



3/2(d+12)=1/2(d-6)

We move all terms to the left:

3/2(d+12)-(1/2(d-6))=0



Domain of the equation: 2(d+12)!=0

d∈R





Domain of the equation: 2(d-6))!=0

d∈R



We calculate fractions


(6dd/(2(d+12)*2(d-6)))+(-2dd/(2(d+12)*2(d-6)))=0



We calculate terms in parentheses: +(6dd/(2(d+12)*2(d-6))), so:

6dd/(2(d+12)*2(d-6))

We multiply all the terms by the denominator


6dd

Back to the equation:

+(6dd)





We calculate terms in parentheses: +(-2dd/(2(d+12)*2(d-6))), so:

-2dd/(2(d+12)*2(d-6))

We multiply all the terms by the denominator


-2dd

Back to the equation:

+(-2dd)



We get rid of parentheses

6dd-2dd=0

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